Hardest Part

HARDEST PART

Hardest Part Q&A

hardest part

Q: How do you know when to use "integration by parts"?

I have a calc test tomorrow, and i want to know that when I see a question, i know what method to use, such as by parts, trig sub. or by partial fraction. it seems that the hardest one to identify is the one to integrate by parts, can someone give me a hint. for example, evauluate the integral of (t)sec^2(2t)dt, if i solve this prob. by parts, which term do i assign it as "u" and which one is "dv"?

A: Whenever, you have a product of two functions: u snd v. Since; D(UV) = UdV + VdU then, ∫UdV = UV - ∫VdU, Let u = t, a simple independent variable is best to assign u. while dV = dependent function of u . So any function nesting will automatically be accounted for in the derivative. Consider, evaluating the integral: ∫ t² sin(t) dt, let u = t, du = dt, dv = sin t, v = -cos t ∫UdV = UV - ∫VdU, = t cos t + ∫ cos t dt = t cos t + sin t + C so, by choosing the independent variable and as it changes value we determine the effect on the product of functions. GL2U!

Hardest Part Q&A Hardest Part

 

 

© 2012 hardestpart.com Contact us - Q&A powered by Yahoo! Answers

Hardest Part